HUGHES TECHNICAL QUESTIONS

There were ten questions in the software section
give the output of the following programs
there were no options given, you have to fill in the given blanks
__________________________________________________________

given A=65
double is 4 byte,int is 2 byte

Q1) this question was based on swaping two varibles

swap(int a,int b)
{
a=a+b;
b=a-b;
a=a-b;
}

main()
{
int a=3;
int b=4;
printf("%d %d\n",a,b);
..............

printf("%d %d",a,b);
}

ans-4 3
4 3
Q2) this question was based on switch statement,break+continue
main()
{
int a=1,b=4;
for (i=0;i<2;i++)
{
switch (a) {
case 1: if (b!=4)
break; // watch out for these
else continue; // two lines
b=....
a=.....
case 2: ....
........
..........
}
}
printf("Output is %d %d",a,b);
}

ans- Output is 1 4
Q3) third question was based on macros
#define dcm(a) a*a
main()
{
int first=3,second=2,var1;
var1=dcm(first+1);
printf("output is %d %d\n",var1++,var1++);
var1=dcm(first++);
printf("output is %d %d",var1++,var1++);
}
ans- output is 8 7
output is 10 9
Q4) what is the output
main()
{
int d;
d=(a&b) ~(~0 ... &c); //there was an expression like this
printf("%d",d);
}
ans- 5

Q5)
fun(char *p1,char *p2)
//this function was displaying the position
{ //the position of DCM in the string
.............
.............
...........
.............
...............
}
main()
{
printf("%d",fun("datasystem","DCM");
printf("%d",fun("DCMDELHI","DCM");
}

ans- -1 ... (for the second answer count the position of DCM in the string)

Q(6)
funct(int var)
{
static int s;
if(var=3) return var;
else { s=s+7;
var=var+1;
funct(var);
}
s=s-var;
return s;
}
main()
{
int munx,munz;
numx=funct(1);
numz=funct(0);
printf("numx=%d numz=%d",numx,numz);
}
ans- numx=9 numz=24



Q9) this question was based on printing char variable using %d flag which prints the ascii value

#include
char a;
func(.......)
{
.........
........
.........
printf("%c",a);
}
main()
{
char a='B';
printf("%d",a);
...........;
printf(................);
.................;
printf(...............);
}
ans- 66BAA66

Q10)
int mask,nbits;
funct(int a) //this function was same as that given
{ //in page 433 in schaum series // c programming book
// this function prints the binary //equivalent of the number passed
for(count=1;count<=nbits;count++) // in blocks of four bits
{ b=(a & mask) ? 1:0;
printf("%x",b);
if(count %4 ==0)
printf(" ");
mask>>1;
}

main()
{
nbits=8*sizeof(int);
mask=0x1 << (nbits -1);
funct(32767);
funct(-32768);
}

ans- 0111 1111 1111 1111 1000 0000 0000 0000